02/13/2017, 01:11 AM

Two ideas are at play here

1) approximate f^[1/2](z) by a^[1/2](z) + b^[1/2](z) when f(z) = a(z) + b(z).

2) q( q x ^ s )^s = q^{s+1} x^(s^2).

So when we try this to approximate 2sinh^[1/2](x), what do we get ?

G(x) = 0 + A1 x + A2 x^sqrt 2 + A3 x^sqrt 3 + ...

Need to think about that.

sent it mick From MSE too , so it might appear there.

Regards

Tommy1729

1) approximate f^[1/2](z) by a^[1/2](z) + b^[1/2](z) when f(z) = a(z) + b(z).

2) q( q x ^ s )^s = q^{s+1} x^(s^2).

So when we try this to approximate 2sinh^[1/2](x), what do we get ?

G(x) = 0 + A1 x + A2 x^sqrt 2 + A3 x^sqrt 3 + ...

Need to think about that.

sent it mick From MSE too , so it might appear there.

Regards

Tommy1729